✔ 最佳答案
a_1,a_2,...,a_n為正等比數列. 令 r = a_n/a_(n-1),
則 a_k = a_1 × r^(k-1).
S = Σ[a_1 × r^(k-1)] = a_1(1-r^n)/(1-r)
T = Σ[ (1/a_1) × r^[-(k-1)]
= (1/a_1)(1-r^(-n))/(1-r^(-1))
= (1/a_1)r^(-n+1)(1-r^n)/(1-r)
S/T = a_1^2 r^(n-1)
a_1 × a_2 × … × a_n = a_1^n r^[1+2+...+(n-1)]
= a_1^n r^[n(n-1)/2]
= (a_1^2 r^(n-1))^(n/2)
= (S/T)^(n/2)