化簡(5+i)(1-2i)/(1+2i)(2-3i)，並以a+bi表示答案；苦(5+i)(1-2i)/(1+2i)(2-3i)=2x-(y/5)i，求數式中x和y的值。?
回答 (1)
2016-12-01 1:40 am
[(5+i)(1-2i)]/[(1+2i)(2-3i)]
=(47/65)-(79/65)i
[(5+i)(1-2i)]/[(1+2i)(2-3i)]=2x-(y/5)i
(47/65)-(79/65)i=2x-(y/5)i
2x=47/65
x=47/130
y/5=79/65
y=79/13
=(47/65)-(79/65)i
[(5+i)(1-2i)]/[(1+2i)(2-3i)]=2x-(y/5)i
(47/65)-(79/65)i=2x-(y/5)i
2x=47/65
x=47/130
y/5=79/65
y=79/13
收錄日期: 2021-04-18 15:52:26
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20161130001146AAtbLvf