7m^9n^2/14m^3n^4 (化簡代數)?
回答 (2)
2016-05-23 8:49 am
(7 m^9 n^2) / (14 m^3 n^4)
= (7/14) (m^9/m^3) (n^2/n^4) ...... 將相同底數分組
= (1/2) m^(9-3) n^(2-4) ...... 指數定律：a^u/a^v = a^(u-v)
= (1/2) m^6 n^(-2)
= (1/2) m^6 (1/n^2) ...... 指數定律：a^(-u) = 1/a^u
= m^6 / (2 n^2)
= (7/14) (m^9/m^3) (n^2/n^4) ...... 將相同底數分組
= (1/2) m^(9-3) n^(2-4) ...... 指數定律：a^u/a^v = a^(u-v)
= (1/2) m^6 n^(-2)
= (1/2) m^6 (1/n^2) ...... 指數定律：a^(-u) = 1/a^u
= m^6 / (2 n^2)
2016-05-23 12:43 pm
(7m^9 n^2)/(14m^3 n^4)
=m^6/(2n^2)
=m^6/(2n^2)
收錄日期: 2021-04-18 14:50:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160522192413AAo2HKA