如圖，若∠CAE=45°，PA=5，PC=1，則BC=?
回答 (1)
2016-01-09 1:10 pm
✔ 最佳答案
∠CAE = 45°∠ACE = 180° - ∠CAE - ∠AEC = 180° - 45° - 90° = 45°
∴ AE = CE ( 等角對邊相等 )
∵ ΔAPE ~ ΔCPD ( AAA )
AE / CD = AP / CP
CE / CD = PA / PC
CD / CE = PC / PA = 1 / 5
∵ ΔPCD ~ ΔBCE ( AAA )
PC / BC = CD / CE = PC / PA = 1 / 5
1 / BC = 1 / 5
BC = 5
收錄日期: 2021-04-18 14:18:44
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