x=3. x+3y=9?

x=3
x+3y=9
3+3y=9
3y=9-3
3y=6
y=6/3
y=2

X=3. X+3y=9
so sub x into the original equation X+3y+9
3+3y=9
move the 3(x) over to the 9 and change side change signs
3y=9-3
than 9-3 = 6 so you will be left with
3y=6
divide both sides by 3 to isloate y
than y=2

Y=2

x=3
3+3y=9
9-3=6
3y=6
6/3 = 2
y=2

3+3y=9
3y=9-3=6
y=6/3=2

Y=6

To zero?

X=3
3 + 3y = 9
3y = 6
y =2

Your question: "X=3. x+3y=9?"

If you like. After all, X and x can be set to represent any numbers you so desires.

If these are supposed to be simultaneous equations, and X and x refer to the same variable, start here:

If x = 3 then x - 3 = 0.
If x + 3y = 9 then x + 3y - 9 = 0

Solve for y in terms of x if possible, or vice verse.

If x + 3y - 9 = 0 then y = (9 - x) / 3.

Substitute the new expression wherever y occurs in the original equation:
x + (9 - x) / 3 - 9 = 0

Since both expressions equal zero, and things equal to the same thing are equal to each other, set the expressions equal to each other:

x - 3 = x + (9 - x) / 3 - 9

Move everything to the left of the equality operator:

x - 3 - x - [ (9 - x) / 3 ] + 9 = 0

If the system is consistent, you will find at least one value for x by solving that equation.

You can substitute that into the original equations to see if it works.

If an absurd answer, there is no solution. It is up to you to figure out why.

If you get something like 0 = 0, you will have to figure out what that means.

I leave it to you to determine what the solution set is, or indeed if there is a solution set.

Once you understand why it is that you get the outcome you get, you are on your way to understanding the mathematical structure at issue.

Don't forget to follow the algebraic order of operations, PEMDAS.

y=2

Here X = 3

So X + 3y = 9
or, 3 +3y = 9
or, 3y = 9 -3
or, y = 6/3

so Y = 2 . Answer

2

Y=2

Y=2

substitute
x=3

(3)+3y=9
3y=6
y=2

(gives you the point (3,2))

x=3 and x+3y=9
x+3y=9
3y=9-x
3y=9-3 (as x=3)
3y=6
y=6/3
y=2
Ans: 2

X=3. x+3y=9?
Plug x=3 into the equation
3+3y=9
-> 3y = 6
->y=2

X=3,

x+3y=9
Substitute the value of x in the above equation.
3+3y=9
3y=9-3
3y=6
y=6/3
y=2

3 + 3y = 9
3 - 3 + 3y = 9 - 3
3y = 6
3y/3 = 6/3
y = 2.

y=2

y=2

y=2

:facepalm:

seriously? you couldn't solve this?

x=3
(3)+3y=9
3y=9-3
3y=6
y=2

The correct way of expression is ,y=(9-3)/3=6/3 = 2

3y = 6

y = 2

y=2

The answer,2

If X=3. x+3y=9, then y=6

(3)+3y=9
subtract 3 from both sides
3y=6
divide both sides by 3
y=2

y=2

x=3
x+3y=9
3+3y=9
3y=9-3
3y=6
y=6/3
y=2

Dang it I remember when this crap was new Algebra 1 right?
Y=2

x+3y = 9
3+3y = 9
-3 -3
3y = 6
3y/3y = 6/3y
y = 2

"x=3. x+3y=9?"
First: Plug x in such that: 3 + 3y = 9
Second: Subtract three from both sides: 3y = 6
At last: Divide by three on both sides: y = 2

12

y=2
because x=3
3+3(2)=9
wh

OK - so what's your question?

Y = 2

x=3. 3+3y =9. 3y=9-3. 3y=6. y=6/3 y=2

x=3
x+3y=9
3+3y=9
3y=9-3
3y=6
y=6/3
y=2 ../@/..

2

3+3y = 9
3y= 9-3
3y=6
y=2

y=2

Y=2. First plug in 3 in place of x so the equation looks like 3+3y=9. Now subtract 3 from both sides: 3y=6. Now divide on both sides. 3y÷3=y and 6÷3=2, so y=2.

1) Substitute 3 for x:

3+3y=9

2) Cross-multiply 3 by adding -3 on *both* sides so that the 3s on the left-hand side cancel out
(OR think as if you were 'moving' +3 to the right-hand side and changing the sign; though, we're not actually 'moving', this is only a quick trick!)

3 - 3 +3y = 9 - 3
3y = 6

3) Divide *both* sides by 3 so that the 3 on the left-hand side becomes 1
y = 6/3
y = 2

y=2

y=25 cuz its the 25th letter in da alfibet

6666

x+3y = 9
3 + 3y = 9
3y = 6
y = 6/3 = 2

simply remove x from equation 2, by replacing the x with 3,,,,,,,,,,,,,,,,,3 + 3y=9, remove the 3 by subtracting it from both sides, 3y=6, then divide both by 3, y=2. It might be tempting to do so, but don't condense steps 1 and 2 into a single step, of not writing x, and subtracting 3 from 9.

X=7+bbq^3

God Dang it so many answers.....

!! (2) y (0)

(x,y)=(3, 2)
Do your HW, m8, this is 8th grade Algebra.

2

3+3y=9
3y=9-3
3y=6
y=2

y>9000

Math in primary school???

Y=2 my friend!

but you didnt mention give the value of y????

3+3y=9
(3-3)+3y=(9-3)
3y=6
(3y/3)=(6/3) Y=2

y=2

To hard

Pardon son lay off the crack pipe.

3 + 3y = 9
-3 -3
3y = 6, y= 2

y equals 2

y=2

2

I was gonna answer this one, but it looks like everyone's already got it covered.

given X=3 and x+3y=9

3 + 3y = 9

==> 3y = 6

==> y = 6/3 = 2

x + 3y = 9 when x = 3.
(3) + 3y = 9
3 + 3y = 9'
3y = 6
y = 2.

Y=2
So the sum is 3+6=9

To work this out take X away from 9 = 6 and divide by the amount of Y's. 6/3 =2

Back to beginning Y=2

y=2

if you subtract three on both sides you get 3y=6
and then divide 6 by 3 to get y=2

Plug x into x + 3y = 9
3 + 3y = 9, 3y = 6, y = 2

Y=2

y=2

y=2

3 + 3y = 9

3y = 6

y = 2

AMAZING! ! You post the problem to the Internet BY Personal computer and CAN'T SOLVE IT
YOURSELF? ? AMAZING! ! and sad. . .

Y=2

Y=2

Y = 2

x + 3y = 9
x = 3
y = 2

Y=2