Evaluate the following:
integral from -1 to 6 ( 9+e^(-2t) )δ(t-2) dt = ??
how to evaluate
plz give me step by step solution
Maths problem?
2015-03-31 12:56 am
回答 (1)
2015-03-31 1:36 am
✔ 最佳答案
The integral will attain the value of its integrand (without the delta function) when the delta function's argument is 0.In this case, this occurs when t = 2 (which is in [-1, 6]).
So, the integral equals 9 + e^(-2*2) = 9 + e^(-4).
I hope this helps!
收錄日期: 2021-04-15 19:00:57
原文連結 [永久失效]:
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