✔ 最佳答案
iv converges as it's a constant: a(1) = sin 1π = 0; a(2) = sin 2π = 0, a(3) = sin 3π = 0 ; all terms will be 0.
iii alternates between -1 and 1
i will also eventually alternate between -1 and 1 (or at least values that are really close to that)
ii which eventually has a limit of 0 (but just gets closer and closer without actually reaching it)
so I'd say ii and iv
I hope someone else will confirm this.... or let me know it's wrong and why...