1)Using induction, prove that 3^(2n+3)+40n-27 is divisible by 64 for all integer n≥1
Clearly indicate the base case and the induction hypothesis.
What I did...
n=1
(3^(5)+40-27)/64 = 4 True that 3^(2n+3)+40n-27 is divisible by 64 for all integer n≥1
Assume
3^(2k+3)+40k-27 is divisible by 64
Show
3^(2(k+1)+3)+40(k+1)-27 is divisible by 64
(3^(2(k+1))+40(k+1)-27)/64 = (3^(2k+3)+40k-27)/64 + the statement n term.
Here is my problem, what is the n term?
the statement that I found is
4,35,309,2770.....
I didn't see any relationship between them
Help!!
Thanks