The sum of three consecutive integers is 36.
(x - 1) + x + (x + 1) = 36
13 is the largest of the three integers.
Let x-1, x & x+1 be the 3 consecutive integers
then
x-1+x+x+1=36
=>
3x=36
=>
x=12
=>
the largest one =12+1=13.
called x the smaller of the three :
3x+3 = 36
x = 33/3 = 11
y = x+1 = 12
z = x+2 = 13
(x-1), x, (x+1)
sum 3x = 36
x = 12
largest = 13
Let x be the largest.
Let x-1 be the next smaller.
Let x-2 be the smallest.
x + x-1 + x-2 = 36
3x - 3 = 36
3x = 39
x = 13
Answer:
The largest number is 13
n + (n + 1) + (n + 2) = 36
3n + 3 = 36
3n = 36 - 3
3n = 33
n = 11
n = 11
n + 1 = 11 + 1 = 12
n + 2 = 11 + 2 = 13 Largest Integer..
The largest integer is 13......Answer//
The average, 12, is the middle one.
They are consecutive integers so the largest is 13.
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X+X+1+X+2=36
3X+3=36
3X=33X=11
11+12+13=36
X+3=13
Three consecutive integers can be expressed like this:
x
x + 1
x + 2
“Sum” means addition, so the sum of three consecutive integers equaling 36 can be expressed like this:
x + (x + 1) + (x + 2) = 36
You should be able to run with that
Write an equation. Call the first integer x. So what's the next consecutive integer? And the next? Add them all together. What do they equal? Solve the equation for x. That gives you the first integer. From that, you know the next 2 consecutive integers.