A(n) 550-Ω and a(n) 2300-Ω resistor are connected in series with a 12-V battery.
What is the voltage across the 2300-Ω resistor?
Express your answer to two significant figures and include the appropriate units
physics question 2/4 ?
2021-04-13 12:36 pm
回答 (2)
2021-04-13 9:54 pm
V(2300) = V*2300/(2300+550) = 12*23/28.5 = 9.68 V
2021-04-13 4:40 pm
Ohm's Law: V = i*R
The source sees or senses 550+2300 = 2850Ω
The current leaving the battery = 12V/2850Ω = 4.21e-3 = 4.21mA
Each resistor in series has the same current = 4.21mA
V = i*R = 0.00421A * 2300Ω = 9.7V <<<<<
Across the 550Ω: 0.00421A*550Ω = 2.3V
V2.3+9.7V = 12V Checks.
Please award Best Answer to the best answer as that is the only reward for efforts to help.
The source sees or senses 550+2300 = 2850Ω
The current leaving the battery = 12V/2850Ω = 4.21e-3 = 4.21mA
Each resistor in series has the same current = 4.21mA
V = i*R = 0.00421A * 2300Ω = 9.7V <<<<<
Across the 550Ω: 0.00421A*550Ω = 2.3V
V2.3+9.7V = 12V Checks.
Please award Best Answer to the best answer as that is the only reward for efforts to help.
2021-04-13 1:02 pm
TRUST: 9.68 V
收錄日期: 2021-04-24 08:43:45
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