Consider the reaction. 2Fe2O3⟶4Fe+3O2Δ𝐻∘rxn=+824.2 kJ  The formation of 26.0 g of O2 results in?

Molar mass of O₂ = 16.0×2 g/mol = 32.0 g/mol
Moles of O₂ formed = (26.0 g) / (32.0 g/mol) = 0.8125 mol

2 Fe₂O₃ → 4 Fe + 3 O₂    ΔHrxn° = 824.2 kJ
On formation of 3 moles of O₂, 824.2 kJ of heat is absorbed.

(824.2 kJ heat absorbed / 3 mol O₂) × (0.8125 mol O₂)
= 223 kJ heat absorbed

The answer:  The absorption of 223 kJ of heat (the last option)