What is the percentage of Silver in Ag2SO4? With steps please.?
2021-03-21 11:16 pm
i need the percentage for silve in Ag2SO4 with steps so i can understand how to calculate the percentage
回答 (2)
2021-03-21 11:22 pm
✔ 最佳答案
Mass of 1 mole of Ag₂SO₄ = (107.9×2 + 32.1 + 16.0×4) g/mol = 311.9 gMass of Ag in 1 mole of Ag₂SO₄ = 107.9×2 g = 215.8 g
Percent of Ag in Ag₂SO₄ = (215.8/311.9) × 100% = 69.2%
2021-03-22 12:52 am
Ag 107.8682 u x 2 = 215.7364 g Ag/Ag2SO4
Ag2SO4 311.799 g/mo
215.7364g/ 311.799g x 100% = 69.1908569302 %
Rounding to 7 sigfigs: 69.19086 %
Ag2SO4 311.799 g/mo
215.7364g/ 311.799g x 100% = 69.1908569302 %
Rounding to 7 sigfigs: 69.19086 %
收錄日期: 2021-04-25 13:42:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20210321151643AAovwDK