Physics problem: would you mind to teach me how to do this question, thanks.?
回答 (2)
2021-03-10 3:30 am
✔ 最佳答案
A) since no distance is done in line with force, no work is done.B) F = m v² / r = m * ω² / r
ω = √Fr/m = √(5*0.40m/0.20kg) ((in KMS system))
Round answer to 1 sigfig since 5 N only had 1 sigfig!!
2021-03-10 2:32 am
(a) No work is done by the tension in the string, as the motion is perpendicular to that force.
(b) The centrifugal force is mv^2/r, or mr(omega)^2, where omega is the angular speed. So if we set
(5 N) = (0.200 kg)(0.40 m) * (omega)^2, we get
omega^2 = 62.5 s^(-2) =>
omega = around 8 rad/s but use a calculator.
(b) The centrifugal force is mv^2/r, or mr(omega)^2, where omega is the angular speed. So if we set
(5 N) = (0.200 kg)(0.40 m) * (omega)^2, we get
omega^2 = 62.5 s^(-2) =>
omega = around 8 rad/s but use a calculator.
收錄日期: 2021-04-11 23:28:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20210309182248AAgEfRC