方程式的除法求解過程?
回答 (1)
2021-03-04 10:23 am
3x-1+x²
=x²+3x-1
2x⁴-7x²-x-3x³
=2x⁴-3x³-7x²-x
=2x²(x²+3x-1)-9x³-5x²-x
=2x²(x²+3x-1)-9x(x²+3x-1)+22x²-10x
=2x²(x²+3x-1)-9x(x²+3x-1)+22(x²+3x-1)-76x+22
=(2x²-9x+22)(x²+3x-1)-76x+22
2x²+9x+22
=x²+3x-1
2x⁴-7x²-x-3x³
=2x⁴-3x³-7x²-x
=2x²(x²+3x-1)-9x³-5x²-x
=2x²(x²+3x-1)-9x(x²+3x-1)+22x²-10x
=2x²(x²+3x-1)-9x(x²+3x-1)+22(x²+3x-1)-76x+22
=(2x²-9x+22)(x²+3x-1)-76x+22
2x²+9x+22
收錄日期: 2021-04-11 23:30:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20210303130603AAzBcht