Does anyone know the answer to this chemistry problem?
2021-03-01 11:22 pm
Potassium permanganate (KMnO4) solutions are used for the determination of iron in samples of unknown concentration. As a laboratory assistant, you are supposed to prepare 1500. mL of a 0.200 M KMnO4 solution. What mass of KMnO4, in grams, do you need?
回答 (2)
2021-03-02 12:24 am
✔ 最佳答案
Molar mass of KMnO₄ = (39.10 + 54.94 + 16.00×4) g/mol = 158.04 g/molMoles of KMnO₄ needed = (0.200 mol/L) × (1500/1000 L) = 0.300 mol
Mass of KMnO₄ needed = (0.300 mol) × (158.04 g/mol) = 47.4 g
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OR:
(0.200 mol KMnO₄ / 1000 mL solution) × (1500 mL solution) × (158.04 g KMnO₄ / 1 mol KMnO₄)
= 47.4 g KMnO₄
2021-03-02 12:52 am
Molar mass KMnO4 = 158.03 g/mol
1500 mL = 1.500 L
1.500 L X 0.200 mol/L X 158.03 g/mol = 47.41 g KMnO4
1500 mL = 1.500 L
1.500 L X 0.200 mol/L X 158.03 g/mol = 47.41 g KMnO4
收錄日期: 2021-04-25 13:51:16
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