A 95.0-kg refrigerator rests on the floor. How much work is required to move it at constant speed?
2021-01-11 4:51 pm
A 95.0-kg refrigerator rests on the floor. How much work is required to move it at constant speed for 4.00 m along the floor against a friction force of 180. N?
回答 (1)
2021-01-11 5:23 pm
✔ 最佳答案
Force required to move the refrigerator at constant speed, F= frictional force
= 180 N
Work required
= F s
= 180 × 4.00
= 720 J
收錄日期: 2021-04-24 09:52:08
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https://hk.answers.yahoo.com/question/index?qid=20210111085103AAtjVIH