✔ 最佳答案
1 + 3sinθcosθ + 2sin²θ - 2sin⁴θ = 0
1 + 3sinθcosθ + 2sin²θ(1 - sin²θ) = 0
1 + 3sinθcosθ + 2sin²θcos²θ = 0
(1 + sinθcosθ)(1 + 2sinθcosθ) = 0
sinθcosθ = -1 or sinθcosθ = -1/2
2sinθcosθ = -2 or 2sinθcosθ = -1
sin(2θ) = -2 (rejected) or sin(2θ) = -1
where 0 ≤ 2θ < 4π (because 0 ≤ θ < 2π)
Therefore,
2θ = 3π/2 or 2θ = 2π + 3π/2 = 7π/2
θ = 3π/4 or 7π/4