A chemical compound consists only of C, H and O. 4 g of the compound treated with an excess of oxygen. 8,784 g of CO2 and 4,842 of H2O.
a) Determine the minimum formula of the compound R:
point a) is easy I found C3H8O but how do I solve b ??
b) Calculate the molecular formula, knowing that from 0.15 moles of compound, suitably treated, 3.36 liters of O2 measured at c.n
Help with molecular formula?
2020-12-10 3:58 pm
回答 (2)
2020-12-10 5:28 pm
✔ 最佳答案
b)Molar volume of O₂ gas = 22.4 L/mol
No. of moles of O₂ formed = (3.36 L) / (22.4 L/mol) = 0.15 mol
Let molecular formula = (C₃H₈O)ₙ
Equation for the reaction:
(C₃H₈O)ₙ + other reactant(s) → (n/2)O₂ + other product(s)
According to the equation, mole ratio (C₃H₈O)ₙ : O₂ = 1 : (n/2)
Actually, mole ratio (C₃H₈O)ₙ : O₂ = 0.15 mol : 0.15 mol = 1 : 1
Hence, 1 : (n/2) = 1 : 1
n = 2
Molecular formula = C₆H₁₆O₂
2020-12-10 4:47 pm
b) Calculate the molecular formula, knowing that from 0.15 moles of compound, suitably treated, 3.36 liters of O2 measured at c.n
C3H8O
What is c.n??? 3.36 L at STP would be the equivalent of 0.15 mol O2
suitably treated??? treated with O2 (as in combustion)? --- or treated with something else to release O2?
= = = = = I can't really do anymore because I don't know what is meant by the terminology
C3H8O
What is c.n??? 3.36 L at STP would be the equivalent of 0.15 mol O2
suitably treated??? treated with O2 (as in combustion)? --- or treated with something else to release O2?
= = = = = I can't really do anymore because I don't know what is meant by the terminology
收錄日期: 2021-04-24 09:52:03
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