Chem help pls?

031

Molar mass of CuSO₄•5H₂O
= (63.5 + 32.1 + 16.0×9 + 1.0×10) g/mol
= 249.6 g/mol

Molarity of CuSO₄ in the first solution
= (0.091/249.6 mol) / (500/1000 L)
= 7.29 × 10⁻⁴ M

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032

Method 1:
Mass of CuSO₄•5H₂O needed to prepare the second 500-mL solution
= (0.091 g) × (2.3/500)
= 4.19 × 10⁻⁴ g

Method 2:
Mass of CuSO₄•5H₂O needed to prepare the second 500-mL solution
= (7.29 × 10⁻⁴ mol/L) × (2.3/500) × (500/1000 L) × (249.6 g/mol)
= 4.19 × 10⁻⁴ g