As PbCl2 dissolves in water, [Pb2+]=0.20 mol/L and [Cl-]= 0.015 mol/L.?

2020-11-20 9:52 am
1) Write the equilibrium expression for the dissolution of PbCl2. 


2) Compute the ion product using the data given.

回答 (1)

2020-11-20 11:05 am
✔ 最佳答案
1)
PbCl₂(s) ⇌ Pb²⁺(aq) + 2Cl⁻(aq)
Equilibrium expression, Ksp = [Pb²⁺] [Cl⁻]²

2)
Ion product, Q
= [Pb²⁺] [Cl⁻]²
= 0.2 × 0.015²
= 4.5 × 10⁻⁵


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