Maths problem: how to do (b), thanks看不到有何相同之處?

2020-11-17 10:09 am

回答 (1)

2020-11-17 10:42 am
(a)(3x+2)(x-1)-2
=3x^2-x-2-2
=3x^2-x-4
=(x+1)(3x-4)
(b)(3y+8)(y+1)-2
=(3y+6+2)(y+2-1)-2
=(3(y+2)+2)(y+2-1)-2
=(y+2+1)(3(y+2)-4)
=(y+3)(3y+2)


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