2x四次-4x三次+X二次+10x-15 因式分解？到底怎麼組啊啊啊 拜託大神解救！！超急?
回答 (2)
2020-11-07 10:56 pm
x^2 x k
2 0 -5
1 -2 3
2 0 -5
1 -2 3
2020-11-07 6:46 pm
2x^4 - 4x^3 + x^2 + 10x - 15
= 2x^4 - 4x^3 + 6x^2 - 5x^2 + 10x - 15
= 2x^2(x^2-2x+3) - 5(x^2-2x+3)
= (2x^2-5)(x^2-2x+3)
= (√2 x - √5)(√2 x +√5)(x^2-2x+3)
= 2x^4 - 4x^3 + 6x^2 - 5x^2 + 10x - 15
= 2x^2(x^2-2x+3) - 5(x^2-2x+3)
= (2x^2-5)(x^2-2x+3)
= (√2 x - √5)(√2 x +√5)(x^2-2x+3)
收錄日期: 2021-05-01 18:34:00
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