What is the gauge pressure of a basketball when you push it down with a force of 30 N, the ball flattens out, and its bottom forms a circular area with a diameter of 2.5 cm?
P = 61100.0 PaP = 132896.7 PaP = 61146.5 PaP = 78000.2 Pa
pls help #3?
2020-11-03 1:19 pm
回答 (1)
2020-11-03 4:50 pm
✔ 最佳答案
Area of flattened basketball that the 30 N force exerts= π × (2.5/2 cm)²
= 3.14 × (1.25/100 m)²
= 4.90625 m²
Gauge pressure of the basketball
= (30 N) / (4.90625 m²)
= 61146.5 N/m²
= 61146.5 Pa
The answer: P = 61146.5 Pa
收錄日期: 2021-04-25 13:55:14
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