A chemist wants to make 5.0 L of a 0.330 MCaCl2 solution. What mass of CaCl2 (in g) should the chemist use? ?
回答 (1)
2020-11-03 10:42 am
✔ 最佳答案
Moles of CaCl₂ = (0.330 mol/L) × (5.0 L) = 1.65 molMolar mass of CaCl₂ = (40.1 + 35.5×2) = 111.1 g/mol)
Mass of CaCl₂ = (1.65 g) × (111.1 g/mol) = 180 g
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OR:
(0.330 mol CaCl₂ / 1 L solution) × (5.0 L solution) × (111.1 g CaCl₂ / 1 mol CaCl₂)
= 180 g CaCl₂
收錄日期: 2021-04-25 13:42:55
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