An argon-ion laser emitted 9.7 x 10^20 photons with a total energy of 63.4 J. What was the wavelength of this light?
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I tried using E=HC/lambda, but I couldn't get the correct answer. Please show me how to do this. Thank you so much.
Calculating wavelength (lambda) of light (please help)?
2020-11-02 10:19 pm
回答 (1)
2020-11-02 10:34 pm
✔ 最佳答案
Energy per photon, E = 63.4 / (9.7 × 10²⁰) JPlanck constant, h = 6.626 × 10⁻³⁴ J s
Speed of light, c = 3.00 × 10⁸ m/s
E = hc/λ
Then, λ = hc/E
Wavelength, λ
= (6.626 × 10⁻³⁴) × (3.00 × 10⁸) / [63.4 / (9.7 × 10²⁰)] m
= 3.04 × 10⁻⁶ m
= 3040 nm
收錄日期: 2021-04-23 23:06:43
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