Test preparation DELTA H help?
回答 (1)
2020-11-02 7:42 pm
Add the two given thermochemical equation together, and cancel P₄(s) and 6Cl₂(g) on each side.
4PCl₅(g) → 4PCl₃(g) + 4Cl₂(g) ΔH = (-2439 + 3438) kJ = +999 kJ
Divided each side of the above thermochemical equation by 4.
PCl₅(g) → PCl₃(g) + Cl₂(g) ΔH = (+999 kJ)/4 = +250 kJ
4PCl₅(g) → 4PCl₃(g) + 4Cl₂(g) ΔH = (-2439 + 3438) kJ = +999 kJ
Divided each side of the above thermochemical equation by 4.
PCl₅(g) → PCl₃(g) + Cl₂(g) ΔH = (+999 kJ)/4 = +250 kJ
收錄日期: 2021-04-24 08:08:49
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