✔ 最佳答案
If you add 0.100 mol NaOH to 1 L of water, you will end up with the same molarity at 40C as you would at 25C. The different Kw and temperature won't matter, as the add OH- overwhelms the slightly different initial [OH-].
[OH-] = 0.100 M
pOH = 1.00
Now, the pH will be slightly different at this temperature, because pKw = 13.53, and pH = 13.53 - 1.00 = 12.53