Consider the reaction, below. If 3.00 moles of NH3, 2.5 moles of Oz and 4.00 moles of H20 are placed in a 1.00 L container (no NO is initially present). If x moles of NH3 reacts, what is the equilibrium concentration of H20?
4 NH3(g) + 5 O2(g) = 4 NO(g) + 6H2O(g)
Chemistry- equilibrium concentration?
2020-10-25 12:01 am
回答 (1)
2020-10-25 12:47 am
✔ 最佳答案
4 NH₃(g) + 5 O₂(g) ⇌ 4 NO(g) + 6H₂O(g)Initial (mol/L): 3.00 2.50 0.00 4.00
Change (mol/L): -4y -5y +4y +6y
Eqm (mol/L): (3.00 - 4y) (2.50 - 5y) 4y (4.00 + 6y)
Change in [NH₃]: -x = -4y
Hence, y = x/4
Equilibrium [H₂O] = (4.00 + 6y) mol/L = [4.00 + 6(x/4)] mol/L = (4.00 + 1.5x) mol/L
收錄日期: 2021-04-24 08:04:18
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https://hk.answers.yahoo.com/question/index?qid=20201024160149AAltrDW