What pressure will 14.0 g of CO exert in a 3.5 L container at 75°C?

Pressure, P = ? atm
Volume, V = 3.5 L
Mass, m = 14.0 g
Molar mass, M = (12.0 + 16.0) g/mol = 28.0 g/mol
Gas constant, R = 0.08206 L atm / (mol K)
Temperature, T = (273 + 75) K = 348 K

PV = nRT  and  n = m/M
Then, PV = (n/M)RT
Hence, P = (m/M)RT/V

Pressure, P = (14.0/28.0) × 0.08206 × 348 / 3.5 = 4.1 atm

The answer: A) 4.1 atm