Maths problem: how to do, thanks?

2020-10-14 11:25 am

回答 (1)

2020-10-14 1:59 pm
✔ 最佳答案
2sin^2(22°)+2sin^2(68°)
    = 2[sih^2(22°)+sin^2(90°-22°)]
    = 2[sin^2(22°)+cos^2(22°)]       (∵ sin(90°-x) = cos(x).)
    = 2         (∵ sin^2(x) + cos^2(x) = 1)


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