solve 4loga(x)=loga(81)?
回答 (5)
2020-10-06 6:58 pm
4 logₐ(x) = logₐ(81)
logₐ(x⁴) = logₐ(81)
x⁴ = 81
x = 3 or x = -3 (rejected for logₐ(-3) is indefined.)
Hence, x = 3
logₐ(x⁴) = logₐ(81)
x⁴ = 81
x = 3 or x = -3 (rejected for logₐ(-3) is indefined.)
Hence, x = 3
2020-10-06 7:50 pm
4log(base a)x = log(base a)81
log(base a)(x^4) = log(base a)81
x^4 = 81
x = 3
log(base a)(x^4) = log(base a)81
x^4 = 81
x = 3
2020-10-06 6:59 pm
Remember 81 - 3^4
Hence
4log(a)X = log(a)3^4
4log(a)X = 4log(a)3
Cancel down by '4'
log(a)X= log(a) 3
Antilog
X = 3
Hence
4log(a)X = log(a)3^4
4log(a)X = 4log(a)3
Cancel down by '4'
log(a)X= log(a) 3
Antilog
X = 3
2020-10-06 9:00 pm
4loga(x) = loga(81);
ie., loga(x^4) = loga(81);
Therefore x^4 = 81;
ie., x = 3;
ie., loga(x^4) = loga(81);
Therefore x^4 = 81;
ie., x = 3;
2020-10-06 9:00 pm
4 log a (x) = log a (81)
x^4 = 81
Solution:
x = 3
x^4 = 81
Solution:
x = 3
收錄日期: 2021-04-24 08:02:38
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https://hk.answers.yahoo.com/question/index?qid=20201006104813AAJTfbS