given that log5(y)=8 find the value of log5(125y)?
回答 (3)
2020-10-06 3:52 pm
log₅(125y)
= log₅(125) + log₅(y)
= log₅(5³) + 8
= 3 log₅(5) + 8
= 3 + 8
= 11
= log₅(125) + log₅(y)
= log₅(5³) + 8
= 3 log₅(5) + 8
= 3 + 8
= 11
2020-10-06 7:53 pm
log(base 5)(125y) =
log(base 5)125 + log(base 5)y =
3 + 8 =
11
log(base 5)125 + log(base 5)y =
3 + 8 =
11
2020-10-06 4:13 pm
Log[5](y) = 8 → recall: Log[a](x) = Ln(x) / Ln(a) ← where a is the base
Ln(y) / Ln(5) = 8
Ln(y) = 8.Ln(5)
= Log[5](125y)
= Ln(125y) / Ln(5)
= [Ln(125) + Ln(y)] / Ln(5)
= [Ln(5³) + Ln(y)] / Ln(5)
= [3.Ln(5) + Ln(y)] / Ln(5) → recall: Ln(y) = 8.Ln(5)
= [3.Ln(5) + 8.Ln(5)] / Ln(5)
= [11.Ln(5)] / Ln(5)
= 11
Ln(y) / Ln(5) = 8
Ln(y) = 8.Ln(5)
= Log[5](125y)
= Ln(125y) / Ln(5)
= [Ln(125) + Ln(y)] / Ln(5)
= [Ln(5³) + Ln(y)] / Ln(5)
= [3.Ln(5) + Ln(y)] / Ln(5) → recall: Ln(y) = 8.Ln(5)
= [3.Ln(5) + 8.Ln(5)] / Ln(5)
= [11.Ln(5)] / Ln(5)
= 11
收錄日期: 2021-05-01 22:34:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20201006072535AA5fQTa