This stoichiometry question in confusing somebody explain to me please. Question in below.?

1 N₂ + 3 H₂ → 2 NH₃
Mole ratio N₂ : H₂ = 1 : 3

No. of moles of N₂ reacted = (14 g) / (28 g/mol) = 0.5 mol
No. of moles of H₂ reacted = (0.5 mol) × 3 = 1.5 mol
Mass of H₂ = (1.5 mol) × (2 g/mol) = 3 g

The answer: c) 3 g

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OR:

(14 g N₂) × (1 mol N₂ / 28 g N₂) × (3 mol H₂ / 1 mol N₂) × (2 g H₂ / 1 mol H₂)
= 3 g N₂

The answer: c) 3 g