Need some help with chem please.?
回答 (2)
2020-09-27 11:29 pm
For quadratic equation ax² + bx + c = 0
x = [-b ± √(b² - 4ac)] / (2a)
4.64x² - 2.43x - 1.41 = 0
x = {-(-2.43) ± √[(-2.43)² - 4 * 4.64 * (-1.41)]} / (2 * 4.64)
x = (2.43 ± √32.0745) / 9.28
x ≈ 0.872 or x ≈ -0.348
x = [-b ± √(b² - 4ac)] / (2a)
4.64x² - 2.43x - 1.41 = 0
x = {-(-2.43) ± √[(-2.43)² - 4 * 4.64 * (-1.41)]} / (2 * 4.64)
x = (2.43 ± √32.0745) / 9.28
x ≈ 0.872 or x ≈ -0.348
2020-09-27 11:06 pm
Yes. How can i help you?
收錄日期: 2021-04-24 08:01:03
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https://hk.answers.yahoo.com/question/index?qid=20200927150241AAjxZst