An electron in the = 6 level of the hydrogen atom relaxes to a lower energy level, emitting light of = 410nm . ?
回答 (1)
2020-09-27 7:59 pm
Rydberg constant, R = 1.097 × 10⁷ m⁻¹ = 1.097 × 10⁻² nm⁻¹
n₂ = 6 to n₁ = ?
Wavelength of light emitted = 410 nm
Rydberg equation: 1/λ = R [(1/n₁²) - (1/n₂²)]
1/410 = (1.097 × 10⁻²) × [(1/n₁²) - (1/6²)]
(1/n₁²) - (1/6²) = 0.2223
1/n₁² = 0.25
Principal level to which the electron relaxed, n₁ = 2
n₂ = 6 to n₁ = ?
Wavelength of light emitted = 410 nm
Rydberg equation: 1/λ = R [(1/n₁²) - (1/n₂²)]
1/410 = (1.097 × 10⁻²) × [(1/n₁²) - (1/6²)]
(1/n₁²) - (1/6²) = 0.2223
1/n₁² = 0.25
Principal level to which the electron relaxed, n₁ = 2
收錄日期: 2021-04-24 08:03:49
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