What is the fourth derivative of V (x) = x^3 - x^2 + x - 1?
回答 (4)
2020-09-24 7:51 pm
V '(x) = 3x^2 - 2x + 1
V ''(x) = 6x - 2
V '''(x) = 6
V ''''(x) = 0
V ''(x) = 6x - 2
V '''(x) = 6
V ''''(x) = 0
2020-09-24 7:39 pm
Highest power of x is 3. Therefore, the fourth derivative is 0.
2020-09-24 5:53 pm
The third derivative is 6
The fourth is the derivative of a constant, hence zero
The fourth is the derivative of a constant, hence zero
收錄日期: 2021-04-12 12:52:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200924074739AA4Ngdc