How many moles are in 1.50 g of ethylamine, CH3CH2NH2? ?

2020-09-23 11:48 pm

回答 (1)

2020-09-24 12:05 am

Molar mass of CH₃CH₂NH₂ = (12.0×2 + 1.0×7 + 14.0) g/mol = 45.0 g/mol
Moles of CH₃CH₂NH₂ = (1.50 g) / (45.0 g/mol) = 0.0333 mol

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