Chemistry question?
2020-09-20 11:17 pm
If a 130.76g sample of Zinc reacts with excess hydrochloric acid, 2.01 moles of H2(g) are produced. Calculate the Molar Mass of Zinc.
回答 (2)
2020-09-21 12:17 am
Balanced equation for the reaction:
Zn + 2HCl → ZnCl₂ + H₂
Mole ratio Zn : H₂ = 1 : 1
Moles of Zn reacted = Moles of H₂ produced = 2.01 mol
Molar mass of Zn = (130.76 g) / (2.01 mol) = 65.1 g/mol
(to 3 sig. fig.)
Zn + 2HCl → ZnCl₂ + H₂
Mole ratio Zn : H₂ = 1 : 1
Moles of Zn reacted = Moles of H₂ produced = 2.01 mol
Molar mass of Zn = (130.76 g) / (2.01 mol) = 65.1 g/mol
(to 3 sig. fig.)
2020-09-20 11:20 pm
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I spend a lot of time on each problem, I just want to make sure it's for a worthwhile cause.
I spend a lot of time on each problem, I just want to make sure it's for a worthwhile cause.
收錄日期: 2021-04-24 07:59:41
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