chemist makes 80.0g sulf trioxide by combining 50.0g oxygenwithunknown amountofsulfur.How chemistmake 100.0g sulf trioxide with no leftovers?
回答 (2)
2020-09-14 4:50 pm
It is given that:
Mass ratio S : O₂ : SO₃ = (80.0 - 50.0) : 50.0 : 80.0 = 3 : 5 : 8
To make 100.0 g of SO₃ with no leftovers:
Mass of S needed = (100.0 g) × (3/8) = 37.5 g
Mass of O₂ needed = (100.0 g) × (5/8) = 62.5 g
Mass ratio S : O₂ : SO₃ = (80.0 - 50.0) : 50.0 : 80.0 = 3 : 5 : 8
To make 100.0 g of SO₃ with no leftovers:
Mass of S needed = (100.0 g) × (3/8) = 37.5 g
Mass of O₂ needed = (100.0 g) × (5/8) = 62.5 g
2020-09-14 1:49 pm
100.0 X 32/80 = 40 g S and 60 g O ... you can provide the sig. figs.
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