at t=30, the temperature of an oven is 120 degrees and increasing by 2 degrees/minute. What is the temperature at t=40?
回答 (8)
I suppose the unit of t is min.
Temperature at (t = 40 min)
= 120° + (2°/min) × [(40 - 30) min]
= 120° + (2°/min) × (10 min)
= 120° + 20°
= 140°
(40-30min) * (2deg/min) = 20 degree change
120 + 20 = 140°
You could model this as y = 2(t-30) + 120
Mistake: t=30 min. or hr. or sec.?
Assume t is in minutes, then
at t=40 min. the temperature
T=120+2(40-30)=140*
Assume oven has a start temperature of x° before being turned on.;
Then temperature t minutes after starting = T(t) = x° + 2t°.;
T(30) = (x+2t)° = (x+2*30)° = (x+60)° = 120° and x = 60.;
T(40) = (x+2*40)° = (60+80)° = 140°.
Increase of 2 degrees per minute for 10 mins is a 20 degree increase on120
Result is 140 degrees,
but if you want an equation,
T(t) = 2t + 60
T(40) = 140
Since the rate of increase is constant, you can use a linear equation:
T(t) = mt + b
You are given the time (t = 30), the temp (T() = 120) and the slope (m = 2).
Solve for the remaining unknown:
120 = 2(30) + b
120 = 60 + b
60 = b
So now your base equation is:
T(t) = 2t + 60
What's the temp at t = 40?
T(40) = 2(40) + 60
T(40) = 80 + 60
T(40) = 140
If at t = 30, the temperature of an oven is 120°
and increasing by 2°/minute, the temperature at t = 40 is 140°.
收錄日期: 2021-04-24 07:59:43
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