A sample of mercury with a mass of 114.0g was combined with 17.9g of oxygen gas, and the resulting reaction gave 123.1g of mercury(II)oxide.?
回答 (4)
2020-09-13 11:10 pm
✔ 最佳答案
Mercury + Oxygen yields Mercury (II) Oxide2Hg + O₂ → 2HgO
HgO is 201+16 = 217 g/mol
Hg is 201 g/mol
O is 16 g/mol
402 g of Hg + 32 g of O₂ → 434 g of HgO
amount of oxygen needed is (32/402)114 g = 9.07 g of oxygen
17.9–9.1 = 8.8 g of oxygen remaining
due to subtraction, accuracy is only two places.
2020-09-13 11:05 pm
According to the law of conservation of mass:
Total mass of reactants reacted
= Total mass of product produced
= 123.1 g
Mass of unreacted reactants left over after the reaction was complete
= (140.0 + 17.9) - 123.1 g
= 34.8 g
Total mass of reactants reacted
= Total mass of product produced
= 123.1 g
Mass of unreacted reactants left over after the reaction was complete
= (140.0 + 17.9) - 123.1 g
= 34.8 g
2020-09-14 3:16 am
114.0 g + 17.9 g = 131.9 g reactants
Mass product = 123.1 g
Mass oxygen unreacted = 131.9-123.1 = 8.80 g oxygen unreacted.
Mass product = 123.1 g
Mass oxygen unreacted = 131.9-123.1 = 8.80 g oxygen unreacted.
2020-09-14 12:52 am
The two previous answers answered two very different questions. Here is a third approach to answering the correct question:
123.1 g HgO / 216.6 g/mol X (1 mol O2 / 2 mol HgO) X 32.00 g/mol O2 = 9.09 g O2 consumed
Mass O2 remaining = 17.9 - 9.09 = 8.8 g O2 remaining
billrussell42's answer is correct.
123.1 g HgO / 216.6 g/mol X (1 mol O2 / 2 mol HgO) X 32.00 g/mol O2 = 9.09 g O2 consumed
Mass O2 remaining = 17.9 - 9.09 = 8.8 g O2 remaining
billrussell42's answer is correct.
收錄日期: 2021-04-24 08:03:34
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