A cell with a potential of 0.15 V has the cell reaction
2Cu2+(aq) + H2 2Cu+(aq) + 2H+(aq)
If the concentrations of the ions were 1.0 M and the pressure of H2 was 1.0 bar, then Eo for the half reaction
Cu2+(aq) + e Cu+(aq) would be:
a. -0.075 V
b. -0.15 V
c. 0.075 V
d. 0.15 V
e. 0.30 V
find E for half reaction?
2020-09-11 4:02 pm
回答 (1)
2020-09-11 4:39 pm
2H⁺(aq) + 2e⁻ ⇌ H₂(g) E°[H⁺(aq)|H₂(aq)] = 0.00 V
Cu²⁺(aq) + e⁻ ⇌ Cu⁺(aq) E°[Cu²⁺(aq)|Cu⁺(aq)] = ? V
For the cell reaction:
2Cu²⁺(aq) + H₂(g) ⇌ 2Cu⁺(aq) + 2H⁺(aq) E°cell = 0.15 V
E°cell = E°(red) - E°(oxid)
0.15 V = E°[Cu²⁺(aq)|Cu⁺(aq)] - (0.00 V)
E°[Cu²⁺(aq)|Cu⁺(aq)] = 0.15 V
The answer: d. 0.15 V
Cu²⁺(aq) + e⁻ ⇌ Cu⁺(aq) E°[Cu²⁺(aq)|Cu⁺(aq)] = ? V
For the cell reaction:
2Cu²⁺(aq) + H₂(g) ⇌ 2Cu⁺(aq) + 2H⁺(aq) E°cell = 0.15 V
E°cell = E°(red) - E°(oxid)
0.15 V = E°[Cu²⁺(aq)|Cu⁺(aq)] - (0.00 V)
E°[Cu²⁺(aq)|Cu⁺(aq)] = 0.15 V
The answer: d. 0.15 V
收錄日期: 2021-04-30 17:19:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20200911080212AA6gOzf