Logs Question help?
Show that 2^(x+1) + 6(2^(x-1)) = 12 can be written as 2(2^(x)) + 3(2^(x)) = 12
I don't get it :(((
回答 (2)
✔ 最佳答案
Law of indices:
nᵃ⁺ᵇ = nᵃ*nᵇ
nᵃ⁻ᵇ = nᵃ/nᵇ
2ˣ⁺¹ + 6(2ˣ⁻¹) = 12
2ˣ * 2¹ + 6(2ˣ/2¹) = 12
2(2ˣ) + 3(2ˣ / 2) = 12
2^(x+1) = 2^x * 2^1 = 2^x * 2 = 2 * 2^x.
Apply the same reasonings to 6(2^(x-1)).
All good?
收錄日期: 2021-04-24 08:00:18
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