A 100.g piece of silver (SH= 0.240 J/g C) with an initial..?

2020-09-09 11:31 am
 A 100.g piece of silver (SH= 0.240 J/g C) with an initial temperature of 80.5 C is placed in 50.0mL of water with an initial temperature of 21.5 C. What is the temperature of the water at equilibrium? How much heat (in J) was transferred from the metal to the water?

回答 (2)

2020-09-09 12:09 pm
✔ 最佳答案
Assume that there is no heat loss to the surroundings.

Heat transferred, q = m c ΔT

Density of water = 1.00 g/mL
Mass of the water = (50.0 mL) × (1.00 g/mL) = 50.00 g

Heat loss by the metal = Heat gained by the water
(100 g) × (0.240 J/g°C) × [(80.5 - T) °C] = (50.00 g) × (4.184 J/g°C) × (T - 21.5)
1932 - 24.0T = 209.2T - 4497.8
233.2T = 6429.8
Temperature at equilibrium, T = 27.6°C (to 3 sig. fig.)

Heat transferred from the metal to the water
= (100 g) × (0.240 J/g°C) × [(80.5 - 27.6) °C]
= 1270 J
2020-09-09 11:34 am
Here's a 100g piece of silver, sculpted into a Tiki


收錄日期: 2021-04-24 08:00:32
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