Suppose a student starts with 2.3935 g of a sand mixture and separates the components, recovering 1.3012 g of
N
a
C
l
, 0.5683 g of
S
i
O
2
, and 0.4503 g of
C
a
C
O
3
.
What is the percent recovery of the mixture?
chemistry trouble?
2020-09-08 1:24 pm
回答 (1)
2020-09-08 2:18 pm
Percent recovery
= [(1.3012 + 0.5683 + 0.4503)/2.3935] × 100%
= 96.921%
= [(1.3012 + 0.5683 + 0.4503)/2.3935] × 100%
= 96.921%
收錄日期: 2021-04-24 08:01:47
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