Suppose a 15.9722 g sample of a
N
a
C
l
and
K
C
l
mixture contains 3.5831 g of
N
a
C
l
.
What is the percent of
K
C
l
in the mixture?
chemistry problems?
2020-09-08 1:20 pm
回答 (2)
2020-09-08 1:31 pm
Percent of KCl in the mixture
= [(15.9722 - 3.5831)/15.9722] × 100%
= 77.567%
====
OR:
Percent of NaCl in the mixture
= (3.5831/15.9722) × 100%
= 22.433%
Percent of KCl in the mixture
= (100 - 22.433)%
= 77.567%
= [(15.9722 - 3.5831)/15.9722] × 100%
= 77.567%
====
OR:
Percent of NaCl in the mixture
= (3.5831/15.9722) × 100%
= 22.433%
Percent of KCl in the mixture
= (100 - 22.433)%
= 77.567%
2020-09-08 1:22 pm
KCl and NaCl are basically the same thing. It's just a lump of salt.
收錄日期: 2021-04-24 08:03:12
原文連結 [永久失效]:
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