Suppose a student starts with 2.4018 g of a sand mixture and separates the components into 1.3012 g of
NaCl
, 0.5613 g of
SiO2
, and 0.4503 g of
CaCO3
Based on the amount of recovered, what is the percent of
SiO2
in the sand mixture?
hard chemistry problem?
2020-09-08 1:19 pm
回答 (1)
2020-09-08 2:28 pm
Based on the amount of recovered, the percent of SiO₂
= [0.5613/(1.3012 + 0.5613 + 0.4503)] × 100%
= 24.27%
= [0.5613/(1.3012 + 0.5613 + 0.4503)] × 100%
= 24.27%
收錄日期: 2021-04-24 08:00:18
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