Maths problem: how to do. (b), thanks?
回答 (1)
2020-09-02 8:38 am
✔ 最佳答案
(2x-3)^2 = (2x)^2 - 2(2x)(3) + 3^2= 4x^2 - 12x + 9
[2(p+q)-3]^2 = 4(p+q)^2 - 12(p+q) + 9
= 4(p^2+2pq+q^2) - 12(p+q) + 9
= 4p^2 +8pq + 4q^2 - 12p -12q + 9
收錄日期: 2021-04-24 07:59:52
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