Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:
3H2(g)+N2(g)→2NH3(g)
How many moles of NH3 can be produced from 24.0 mol of H2 and excess N2?
Express the number of moles to three significant figures.
chemistry question?
2020-09-02 12:27 am
回答 (1)
2020-09-02 12:39 am
3H₂(g) + N₂(g) → 2NH₃(g)
Mole ratio H₂ : NH₃ = 3 : 2
No. of moles of NH₃ produced = (24.0 mol) × (2/3) = 16.0 mol
Mole ratio H₂ : NH₃ = 3 : 2
No. of moles of NH₃ produced = (24.0 mol) × (2/3) = 16.0 mol
收錄日期: 2021-05-01 22:38:21
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