A football receiver runs 10m downfield in 1.7 sec and then reverses 2 m in 1 sec. He catches the ball and runs for a touchdown 45 m in 7 sec. Calculate the average velocity for the three intervals and for the entire motion.
I got this bit I don't know if I did the equation correctly
V1= 10m/1.7s= 6.67 m/s
V2=2m/1s=2m/s
V3= 45m/7s=6.43 m/s
10m-2m=8
45+8=53m
1.7+7+1=9.7 sec
average= 5.46 m/s
Time, Velocity, Speed?
2020-08-30 11:01 pm
回答 (1)
2020-08-30 11:26 pm
For the interval of running 10 m downfield in 1.7 sec:
Average velocity = 10/1.7 = 5.9 m/sec
For the interval of reversing 2 m in 1 sec:
Average velocity = -2/1 = -2 m/sec
For the interval of running for a touchdown 45 m in 7 sec:
Average velocity = 45/7 = 6.4 m/sec
For the entire motion:
Average velocity = (10 - 2 + 45) / (1.7 + 1 + 7) = 5.5 m/sec
Average velocity = 10/1.7 = 5.9 m/sec
For the interval of reversing 2 m in 1 sec:
Average velocity = -2/1 = -2 m/sec
For the interval of running for a touchdown 45 m in 7 sec:
Average velocity = 45/7 = 6.4 m/sec
For the entire motion:
Average velocity = (10 - 2 + 45) / (1.7 + 1 + 7) = 5.5 m/sec
收錄日期: 2021-04-24 07:58:08
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